问HN:垂直和水平微指令格式?

1作者: shivajikobardan3 个月前原帖
以下答案是由claude.ai提供的。我只是想验证一下这是否正确。 水平微指令和垂直微指令之间的确切区别在于控制信号在微指令字中的编码方式: *水平微指令:* - 微指令中的每一位直接对应一个特定的控制信号 - 如果有20个控制信号,则微指令需要20位 - 每个位的位置都有特定的含义(例如,位0 = ALU使能,位1 = 寄存器写入,位2 = 内存读取等) - 微指令本质上是一个位向量,每一位直接控制一个硬件组件 - 示例:`101001010...`,其中每个位置直接开启/关闭特定的控制线 *垂直微指令:* - 控制信号通过编码方案使用更少的位进行编码 - 多个控制信号被组合在一起,并通过编码字段表示 - 使用解码器将编码字段转换回单独的控制信号 - 微指令中的每个字段表示一组互斥或相关的操作 - 示例:与其为8种不同的ALU操作使用8个独立的位,不如使用3个位来编码要执行的8种操作中的哪一种 *形成示例:* 假设您需要控制:ALU操作(8种可能性)、寄存器选择(4个寄存器)、内存操作(读取/写入/无) - *水平*:需要至少8 + 4 + 2 = 14位(每个控制信号一位) - *垂直*:需要3 + 2 + 2 = 7位(编码字段:ALU操作3位,寄存器2位,内存2位) 关键的形成区别在于:水平微指令使用直接的位到控制的映射,而垂直微指令使用需要解码硬件的编码字段。
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The below answer has been provided with claude.ai. I am just trying to verify whether this is correct or not.<p>The exact difference between horizontal and vertical microinstructions lies in how the control signals are encoded within the microinstruction word:<p>*Horizontal Microinstructions:* - Each bit in the microinstruction directly corresponds to a specific control signal - If you have 20 control signals, you need 20 bits in the microinstruction - Each bit position has a dedicated meaning (e.g., bit 0 = ALU enable, bit 1 = register write, bit 2 = memory read, etc.) - The microinstruction is essentially a bit vector where each bit directly controls one hardware component - Example: `101001010...` where each position directly turns on&#x2F;off a specific control line<p>*Vertical Microinstructions:* - Control signals are encoded using fewer bits through encoding schemes - Multiple control signals are grouped together and represented by encoded fields - Uses decoders to convert the encoded fields back to individual control signals - Each field in the microinstruction represents a group of mutually exclusive or related operations - Example: Instead of having 8 separate bits for 8 different ALU operations, you use 3 bits to encode which of the 8 operations to perform<p>*Formation Example:* Say you need to control: ALU operation (8 possibilities), Register selection (4 registers), Memory operation (read&#x2F;write&#x2F;none)<p>- *Horizontal*: Need 8 + 4 + 2 = 14 bits minimum (one bit per control signal) - *Vertical*: Need 3 + 2 + 2 = 7 bits (encoded fields: 3 bits for ALU ops, 2 bits for register, 2 bits for memory)<p>The key formation difference is: horizontal uses direct bit-to-control mapping, while vertical uses encoded fields that require decoding hardware.